22.95=3.14(2x)^2

Solution for 22.95=3.14(2x)^2 equation:

22.95=3.14(2x)^2

We move all terms to the left:

22.95-(3.14(2x)^2)=0

We get rid of parentheses

-3.142x^2+22.95=0

a = -3.142; b = 0; c = +22.95;
Δ = b2-4ac
Δ = 02-4·(-3.142)·22.95
Δ = 288.4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{288.4356}}{2*-3.142}=\frac{0-\sqrt{288.4356}}{-6.284}
=-\frac{\sqrt{}}{-6.284}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{288.4356}}{2*-3.142}=\frac{0+\sqrt{288.4356}}{-6.284}
=\frac{\sqrt{}}{-6.284}
$